GeetCode Hub

On a broken calculator that has a number showing on its display, we can perform two operations:

  • Double: Multiply the number on the display by 2, or;
  • Decrement: Subtract 1 from the number on the display.

Initially, the calculator is displaying the number x.

Return the minimum number of operations needed to display the number y.

 

Example 1:

Input: x = 2, y = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.

Example 2:

Input: x = 5, y = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.

Example 3:

Input: x = 3, y = 10
Output: 3
Explanation:  Use double, decrement and double {3 -> 6 -> 5 -> 10}.

Example 4:

Input: x = 1024, y = 1
Output: 1023
Explanation: Use decrement operations 1023 times.

 

Note:

  1. 1 <= x <= 109
  2. 1 <= y <= 109

class Solution { public int brokenCalc(int x, int y) { } }