# GeetCode Hub

Implement a last in first out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal queue (`push`, `top`, `pop`, and `empty`).

Implement the `MyStack` class:

• `void push(int x)` Pushes element x to the top of the stack.
• `int pop()` Removes the element on the top of the stack and returns it.
• `int top()` Returns the element on the top of the stack.
• `boolean empty()` Returns `true` if the stack is empty, `false` otherwise.

Notes:

• You must use only standard operations of a queue, which means only `push to back`, `peek/pop from front`, `size`, and `is empty` operations are valid.
• Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue), as long as you use only a queue's standard operations.

Example 1:

```Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]

Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return False
```

Constraints:

• `1 <= x <= 9`
• At most `100` calls will be made to `push`, `pop`, `top`, and `empty`.
• All the calls to `pop` and `top` are valid.

Follow-up: Can you implement the stack using only one queue?

class MyStack { /** Initialize your data structure here. */ public MyStack() { } /** Push element x onto stack. */ public void push(int x) { } /** Removes the element on top of the stack and returns that element. */ public int pop() { } /** Get the top element. */ public int top() { } /** Returns whether the stack is empty. */ public boolean empty() { } } /** * Your MyStack object will be instantiated and called as such: * MyStack obj = new MyStack(); * obj.push(x); * int param_2 = obj.pop(); * int param_3 = obj.top(); * boolean param_4 = obj.empty(); */