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Strings s1 and s2 are k-similar (for some non-negative integer k) if we can swap the positions of two letters in s1 exactly k times so that the resulting string equals s2.

Given two anagrams s1 and s2, return the smallest k for which s1 and s2 are k-similar.

 

Example 1:

Input: s1 = "ab", s2 = "ba"
Output: 1

Example 2:

Input: s1 = "abc", s2 = "bca"
Output: 2

Example 3:

Input: s1 = "abac", s2 = "baca"
Output: 2

Example 4:

Input: s1 = "aabc", s2 = "abca"
Output: 2

 

Constraints:

  • 1 <= s1.length <= 20
  • s2.length == s1.length
  • s1 and s2 contain only lowercase letters from the set {'a', 'b', 'c', 'd', 'e', 'f'}.
  • s2 is an anagram of s1.

class Solution { public int kSimilarity(String s1, String s2) { } }