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We are given head, the head node of a linked list containing unique integer values.

We are also given the list nums, a subset of the values in the linked list.

Return the number of connected components in nums, where two values are connected if they appear consecutively in the linked list.

Example 1:

Input: 
head: 0->1->2->3
nums = [0, 1, 3]
Output: 2
Explanation: 
0 and 1 are connected, so [0, 1] and [3] are the two connected components.

Example 2:

Input: 
head: 0->1->2->3->4
nums = [0, 3, 1, 4]
Output: 2
Explanation: 
0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.

Note:

  • If n is the length of the linked list given by head1 <= n <= 10000.
  • The value of each node in the linked list will be in the range [0, n - 1].
  • 1 <= nums.length <= 10000.
  • nums is a subset of all values in the linked list.

# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def numComponents(self, head: ListNode, nums: List[int]) -> int: