# GeetCode Hub

We are given `head`, the head node of a linked list containing unique integer values.

We are also given the list `nums`, a subset of the values in the linked list.

Return the number of connected components in `nums`, where two values are connected if they appear consecutively in the linked list.

Example 1:

```Input:
nums = [0, 1, 3]
Output: 2
Explanation:
0 and 1 are connected, so [0, 1] and [3] are the two connected components.
```

Example 2:

```Input:
nums = [0, 3, 1, 4]
Output: 2
Explanation:
0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.
```

Note:

• If `n` is the length of the linked list given by `head``1 <= n <= 10000`.
• The value of each node in the linked list will be in the range` [0, n - 1]`.
• `1 <= nums.length <= 10000`.
• `nums` is a subset of all values in the linked list.

# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def numComponents(self, head: ListNode, nums: List[int]) -> int: