In a group of N people (labelled
0, 1, 2, ..., N-1), each person has different amounts of money, and different levels of quietness.
For convenience, we'll call the person with label
x, simply "person
We'll say that
richer[i] = [x, y] if person
x definitely has more money than person
y. Note that
richer may only be a subset of valid observations.
Also, we'll say
quiet[x] = q if person x has quietness
answer[x] = y if
y is the least quiet person (that is, the person
y with the smallest value of
quiet[y]), among all people who definitely have equal to or more money than person
Input: richer = [[1,0],[2,1],[3,1],[3,7],[4,3],[5,3],[6,3]], quiet = [3,2,5,4,6,1,7,0] Output: [5,5,2,5,4,5,6,7] Explanation: answer = 5. Person 5 has more money than 3, which has more money than 1, which has more money than 0. The only person who is quieter (has lower quiet[x]) is person 7, but it isn't clear if they have more money than person 0. answer = 7. Among all people that definitely have equal to or more money than person 7 (which could be persons 3, 4, 5, 6, or 7), the person who is the quietest (has lower quiet[x]) is person 7. The other answers can be filled out with similar reasoning.
1 <= quiet.length = N <= 500
0 <= quiet[i] < N, all
0 <= richer.length <= N * (N-1) / 2
0 <= richer[i][j] < N
richer[i] != richer[i]
richer[i]'s are all different.
richerare all logically consistent.