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You are given a binary string binary consisting of only 0's or 1's. You can apply each of the following operations any number of times:

  • Operation 1: If the number contains the substring "00", you can replace it with "10".
    • For example, "00010" -> "10010"
  • Operation 2: If the number contains the substring "10", you can replace it with "01".
    • For example, "00010" -> "00001"

Return the maximum binary string you can obtain after any number of operations. Binary string x is greater than binary string y if x's decimal representation is greater than y's decimal representation.

 

Example 1:

Input: binary = "000110"
Output: "111011"
Explanation: A valid transformation sequence can be:
"000110" -> "000101" 
"000101" -> "100101" 
"100101" -> "110101" 
"110101" -> "110011" 
"110011" -> "111011"

Example 2:

Input: binary = "01"
Output: "01"
Explanation: "01" cannot be transformed any further.

 

Constraints:

  • 1 <= binary.length <= 105
  • binary consist of '0' and '1'.

class Solution { public String maximumBinaryString(String binary) { } }