# GeetCode Hub

You are given a binary string `binary` consisting of only `0`'s or `1`'s. You can apply each of the following operations any number of times:

• Operation 1: If the number contains the substring `"00"`, you can replace it with `"10"`.
• For example, `"00010" -> "10010`"
• Operation 2: If the number contains the substring `"10"`, you can replace it with `"01"`.
• For example, `"00010" -> "00001"`

Return the maximum binary string you can obtain after any number of operations. Binary string `x` is greater than binary string `y` if `x`'s decimal representation is greater than `y`'s decimal representation.

Example 1:

```Input: binary = "000110"
Output: "111011"
Explanation: A valid transformation sequence can be:
"000110" -> "000101"
"000101" -> "100101"
"100101" -> "110101"
"110101" -> "110011"
"110011" -> "111011"
```

Example 2:

```Input: binary = "01"
Output: "01"
Explanation: "01" cannot be transformed any further.
```

Constraints:

• `1 <= binary.length <= 105`
• `binary` consist of `'0'` and `'1'`.

class Solution { public String maximumBinaryString(String binary) { } }