# GeetCode Hub

You have `n` packages that you are trying to place in boxes, one package in each box. There are `m` suppliers that each produce boxes of different sizes (with infinite supply). A package can be placed in a box if the size of the package is less than or equal to the size of the box.

The package sizes are given as an integer array `packages`, where `packages[i]` is the size of the `ith` package. The suppliers are given as a 2D integer array `boxes`, where `boxes[j]` is an array of box sizes that the `jth` supplier produces.

You want to choose a single supplier and use boxes from them such that the total wasted space is minimized. For each package in a box, we define the space wasted to be `size of the box - size of the package`. The total wasted space is the sum of the space wasted in all the boxes.

• For example, if you have to fit packages with sizes `[2,3,5]` and the supplier offers boxes of sizes `[4,8]`, you can fit the packages of size-`2` and size-`3` into two boxes of size-`4` and the package with size-`5` into a box of size-`8`. This would result in a waste of `(4-2) + (4-3) + (8-5) = 6`.

Return the minimum total wasted space by choosing the box supplier optimally, or `-1` if it is impossible to fit all the packages inside boxes. Since the answer may be large, return it modulo `109 + 7`.

Example 1:

```Input: packages = [2,3,5], boxes = [[4,8],[2,8]]
Output: 6
Explanation: It is optimal to choose the first supplier, using two size-4 boxes and one size-8 box.
The total waste is (4-2) + (4-3) + (8-5) = 6.
```

Example 2:

```Input: packages = [2,3,5], boxes = [[1,4],[2,3],[3,4]]
Output: -1
Explanation: There is no box that the package of size 5 can fit in.
```

Example 3:

```Input: packages = [3,5,8,10,11,12], boxes = [,[11,9],[10,5,14]]
Output: 9
Explanation: It is optimal to choose the third supplier, using two size-5 boxes, two size-10 boxes, and two size-14 boxes.
The total waste is (5-3) + (5-5) + (10-8) + (10-10) + (14-11) + (14-12) = 9.
```

Constraints:

• `n == packages.length`
• `m == boxes.length`
• `1 <= n <= 105`
• `1 <= m <= 105`
• `1 <= packages[i] <= 105`
• `1 <= boxes[j].length <= 105`
• `1 <= boxes[j][k] <= 105`
• `sum(boxes[j].length) <= 105`
• The elements in `boxes[j]` are distinct.

class Solution { public int minWastedSpace(int[] packages, int[][] boxes) { } }