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Given an array of integers nums, half of the integers in nums are odd, and the other half are even.

Sort the array so that whenever nums[i] is odd, i is odd, and whenever nums[i] is even, i is even.

Return any answer array that satisfies this condition.

 

Example 1:

Input: nums = [4,2,5,7]
Output: [4,5,2,7]
Explanation: [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.

Example 2:

Input: nums = [2,3]
Output: [2,3]

 

Constraints:

  • 2 <= nums.length <= 2 * 104
  • nums.length is even.
  • Half of the integers in nums are even.
  • 0 <= nums[i] <= 1000

 

Follow Up: Could you solve it in-place?

class Solution { public int[] sortArrayByParityII(int[] nums) { } }