You are given a string `s`

that consists of only digits.

Check if we can split `s`

into **two or more non-empty substrings** such that the **numerical values** of the substrings are in **descending order** and the **difference** between numerical values of every two **adjacent** **substrings** is equal to `1`

.

- For example, the string
`s = "0090089"`

can be split into`["0090", "089"]`

with numerical values`[90,89]`

. The values are in descending order and adjacent values differ by`1`

, so this way is valid. - Another example, the string
`s = "001"`

can be split into`["0", "01"]`

,`["00", "1"]`

, or`["0", "0", "1"]`

. However all the ways are invalid because they have numerical values`[0,1]`

,`[0,1]`

, and`[0,0,1]`

respectively, all of which are not in descending order.

Return `true`

*if it is possible to split* `s`

*as described above**, or *`false`

* otherwise.*

A **substring** is a contiguous sequence of characters in a string.

**Example 1:**

Input:s = "1234"Output:falseExplanation:There is no valid way to split s.

**Example 2:**

Input:s = "050043"Output:trueExplanation:s can be split into ["05", "004", "3"] with numerical values [5,4,3]. The values are in descending order with adjacent values differing by 1.

**Example 3:**

Input:s = "9080701"Output:falseExplanation:There is no valid way to split s.

**Example 4:**

Input:s = "10009998"Output:trueExplanation:s can be split into ["100", "099", "98"] with numerical values [100,99,98]. The values are in descending order with adjacent values differing by 1.

**Constraints:**

`1 <= s.length <= 20`

`s`

only consists of digits.

class Solution:
def splitString(self, s: str) -> bool: