Alice and Bob continue their games with piles of stones. There are several stones **arranged in a row**, and each stone has an associated value which is an integer given in the array `stoneValue`

.

Alice and Bob take turns, with **Alice** starting first. On each player's turn, that player can take **1, 2 or 3 stones** from the **first** remaining stones in the row.

The score of each player is the sum of values of the stones taken. The score of each player is **0** initially.

The objective of the game is to end with the highest score, and the winner is the player with the highest score and there could be a tie. The game continues until all the stones have been taken.

Assume Alice and Bob **play optimally**.

Return *"Alice"* if Alice will win, *"Bob"* if Bob will win or *"Tie"* if they end the game with the same score.

**Example 1:**

Input:values = [1,2,3,7]Output:"Bob"Explanation:Alice will always lose. Her best move will be to take three piles and the score become 6. Now the score of Bob is 7 and Bob wins.

**Example 2:**

Input:values = [1,2,3,-9]Output:"Alice"Explanation:Alice must choose all the three piles at the first move to win and leave Bob with negative score. If Alice chooses one pile her score will be 1 and the next move Bob's score becomes 5. The next move Alice will take the pile with value = -9 and lose. If Alice chooses two piles her score will be 3 and the next move Bob's score becomes 3. The next move Alice will take the pile with value = -9 and also lose. Remember that both play optimally so here Alice will choose the scenario that makes her win.

**Example 3:**

Input:values = [1,2,3,6]Output:"Tie"Explanation:Alice cannot win this game. She can end the game in a draw if she decided to choose all the first three piles, otherwise she will lose.

**Example 4:**

Input:values = [1,2,3,-1,-2,-3,7]Output:"Alice"

**Example 5:**

Input:values = [-1,-2,-3]Output:"Tie"

**Constraints:**

`1 <= values.length <= 50000`

`-1000 <= values[i] <= 1000`

class Solution {
public String stoneGameIII(int[] stoneValue) {
}
}