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We define the string s to be the infinite wraparound string of "abcdefghijklmnopqrstuvwxyz", so s will look like this:

  • "...zabcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyzabcd....".

Given a string p, return the number of unique non-empty substrings of p are present in s.


Example 1:

Input: p = "a"
Output: 1
Explanation: Only the substring "a" of p is in s.

Example 2:

Input: p = "cac"
Output: 2
Explanation: There are two substrings ("a", "c") of p in s.

Example 3:

Input: p = "zab"
Output: 6
Explanation: There are six substrings ("z", "a", "b", "za", "ab", and "zab") of p in s.



  • 1 <= p.length <= 105
  • p consists of lowercase English letters.

class Solution { public int findSubstringInWraproundString(String p) { } }